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The displacemeent of a particle is given at time t by x = A sin(-2omega t) + B sin^(2)omegat. Then, |
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Answer» the motion of the particle is SHM with an amplitude of `sqrt(A^(2) + B^(2)/4)` `-A sin 2omega t + B/2 (1- cos2 omega t)` `=(-A sin 2omegat + B/2 COS 2omegat) + B/2` This motion represents SHM with an amplitude `sqrt(A^(2) + (B^(2)//4))`, and mean position of B/2. |
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