The displacement of a partical as a function of time t is given by `s=alpha+betat+gammat^(2)+deltat^(4)`, where `alpha`,`beta`,`gamma` and `delta` are constants. Find the ratio of the initial velocity to the initial acceleration.

The displacement of a partical as a function of time t is given by `s=

1.	The displacement of a partical as a function of time t is given by `s=alpha+betat+gammat^(2)+deltat^(4)`, where `alpha`,`beta`,`gamma` and `delta` are constants. Find the ratio of the initial velocity to the initial acceleration.
Answer» First find the velocity and acceleration in terms of time t, then use t=0 to find the intial values. `s=alpha+betat+gammat^(2)+deltat^(4)` `v=(ds)/(dt)=0+beta.1+gamma.2t+delta.4t^(3)` `=beta+2gammat+4deltat^(3)` `a=(dv)/(dt)=0+2gamma.1+4delta.3t^(2)` `=2gamma+12deltat^(2)` At `t=0, v=beta, a=2gamma` `("Initial velocity")/("Initial acceleration")=beta/(2gamma)`

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The displacement of a partical as a function of time t is given by `s=alpha+betat+gammat^(2)+deltat^(4)`, where `alpha`,`beta`,`gamma` and `delta` are constants. Find the ratio of the initial velocity to the initial acceleration.

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