InterviewSolution
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InterviewSolution
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The displacement of a particle in S.H.M. varies according to the relationx = 4(cos pi t + sin pit) . The amplitude of the particle is |
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Answer» `-4` `= 4sqrt(2) (1/sqrt(2) cos pit + 1/sqrt(2) sin pit)` `=4sqrt(2) [sin pi/4 cos pi t + cos pi/4 sin pit]` `=4sqrt(2) [sin pit cos pi/4 + cos pi t sin pi/4]` `=4sqrt(2) sin (pi t + pi/4)` HENCE, the AMPLITUDE of particle is `4sqrt(2)`. |
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