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The displacement of a particle moving in one dimension under the action of a constant force is related to timer by the equation t= sqrt(x + 3), where x is in metres and in second. What is the displacement of particle when its velocity is zero? |
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Answer» Solution :`tsqrt(x)+3 implies SQRT(x)=t-3 implies x=t^(2)+9-6t` `(dx)/(dt)=2t-6 implies 0=2t-6 implies t=3 s` `:. X=(3)^(2) +9-6xx3=0` or `(dt)/(dx)=(1)/(2)x^(-1//2)+0 implies (dx)/(dt)=2x^(1//2)` `implies 0=2x^(1//2)impliesx=0` |
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