The displacement of a particle of mass 2 g executing SHM is given by y=5sin(4t+pi/3). Here, y is in metres and t is in seconds. The kinetic energy of the particle, when t=T/4 is

The displacement of a particle of mass 2 g executing SHM is given by y

1.	The displacement of a particle of mass 2 g executing SHM is given by y=5sin(4t+pi/3). Here, y is in metres and t is in seconds. The kinetic energy of the particle, when t=T/4 is
Answer» 0.4 J 0.5 J 3 J 0.3 J Solution :Given, `y=5sin(4t+pi/3)` `omega=4and"so "T=(2pi)/4=pi/2s` `t=T/4=pi/8s` Velocity = `(DY)/(dt)=20cos(4t+pi/3)` Velocity at `t=pi/8s` is `v=20cos(4xxpi/8+pi/3)=20cos150^(@)` = `-20cos30^(@)=-(20sqrt3)/2MS^(-1)` KE of particle is `K=1/2mv^(2)=1/2xx2/1000xx100xx3=0.3J`

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The displacement of a particle of mass 2 g executing SHM is given by y=5sin(4t+pi/3). Here, y is in metres and t is in seconds. The kinetic energy of the particle, when t=T/4 is

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