InterviewSolution
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InterviewSolution
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The displacement of a string is given by `y(x,t)=0.06sin(2pix//3)cos(120pit)` where x and y are in m and t in s. The lengthe of the string is 1.5m and its mass is `3.0xx10^(-2)kg.`A. It represents a progresssive wave of frquency 60HzB. It represens a stationary wave of frequency 60HzC. It is the result superpositon of two waves of wavelength 3m , frequency 60 Hz each travelling with a speed of 180 m/s in ipposite directionD. Amplitude of this wave is constant |
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Answer» Correct Answer - B::C Given equation is `" " y(x,t)=0.06 sin ((2pix)/(3)) cos (120pit)` (a) Comparing with a standard equation of staionary wave `" " x(x,t)=a sin (kx) cos (omegat)` Clearly, the given equation belongs to stationary wave. Hence , options (a) is not correct. (b) By comparing. `rArr" " omega=120pi` `" " 2pif==120pirArrf=60Hz` (c) `k=(2pi)/(3)=(2pi)/(lambda)` `rArr" " lambda` = wavelength =3m `" "` Frequency =f=60Hz `" "` speed = `flambda` =(60Hz)(3m)=180m/s (d) Since in stationary wave, all particless of the medium execute SHM with varying amplitude nodes. |
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