1.

The displacement of the interfering light wates are y_(1) = 4 sin omega t and y_(2) = 3 sin(omega t + (pi)/(2)).The amplitude of the resultant wvae is :

Answer»

5
7
1
0

Solution :Here `PHI = pi/2, a_(1) = 4 ` and `a_(2) = 3`
`therefore` RESULTANT amplitude, `a_(R) = sqrt(a_(1)^(2) +a_(2)^(2))`
` = sqrt (4^(2) + 3^(2)) = sqrt 25 = 5`


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