InterviewSolution
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InterviewSolution
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The displacement `x` of particle moving in one dimension, under the action of a constant force is related to the time `t` by the equation ` t = sqrt(x) +3` where `x is in meters and t in seconds` . Find (i) The displacement of the particle when its velocity is zero , and (ii) The work done by the force in the first ` 6 seconds`.A. `18 m`B. zeroC. `9 m//2`D. `36 m` |
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Answer» Correct Answer - B Here `t = sqrtx+ 3 or x = (t - 3)^(2) = t^(2) - 6t + 9` `v = (dx)/(dt) = 2t + 6` at `t = 0, v = 2 xx 0 - 6 = - 6` at `t = 6 s, v = 2 xx 6 - 6 = +6` Initial and final `KE` ar esame hence no work is done. |
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