1.

The displacemnet of particle executing simple harmonic motion is given by y=5/pi sin(20pi t)m, then what is its amplitude ?

Answer»

Solution :`y=a SIN omegat _____(i)`
`y=5/pi sin(20pit) ____(ii)`
by COMPARING EQUATION (ii) with standard EQUTION(i) we get `a=5/pi`


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