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The displacemnet of particle executing simple harmonic motion is given by y=5/pi sin(20pi t)m, then what is its amplitude ? |
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Answer» Solution :`y=a SIN omegat _____(i)` `y=5/pi sin(20pit) ____(ii)` by COMPARING EQUATION (ii) with standard EQUTION(i) we get `a=5/pi` |
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