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The dissolution of `1 mol e` of `NaOH_((s))` in `100 mol e` of `H_(2)O_((l))` give rise to evolution of heat equal to `-42.34kJ` . However if `1 mol e` of `NaOH_((s))` is dissolved in `1000 mol e `of `H_(2)O_((l))`, the heat given out is `42.76kJ`. What would be enthalpy change when 900 mole of `H_(2)O_((l))` are added to a solution containing 1 mole of `NaOH_((s))` in 100 mole of `H_(2)O` ? |
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Answer» Correct Answer - `-0.42kJ;` |
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