The distance between the lines `(x+7y)^2+4sqrt(2)(x+7y)-42=0`is_______

1.	The distance between the lines `(x+7y)^2+4sqrt(2)(x+7y)-42=0`is_____________
Answer» Correct Answer - 2 `(x+7y)=4sqrt(2)(x+7y)-42=0` or `(x+7y)^(2)+7sqrt(2)(x+7y)-3sqrt(2)(x+7y)-42=0` or `(x+7y)[x+7y+7sqrt(2)]-3sqrt(2)(x+7y+7sqrt(2))=0` or `(x+7y+7sqrt(2))(x+7y-3sqrt(2))=0` or `x+7y+7sqrt(2)=0andx+7y-3sqrt(2)=0` or `d=\|(7sqrt(2)+2sqrt(2))/(sqrt(1+49))\|=(10sqrt(2))/(sqrt(50))=2`

Discussion

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