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The distance between the point of suspension and the centre of gravity of a compound pendulum is `l` and the radius of gyration about the horizontal axis through the centre of gravity is `k`, then its time period will beA. `2pisqrt((l+k)/(g))`B. `2pisqrt((l^(2)+k^(2))/(lg))`C. `2pisqrt((l+k^(2))/(g))`D. `2pisqrt((2k)/(lg))` |
Answer» Correct Answer - B `T = 2pisqrt((l)/(mgl)) = 2pisqrt((l^(2) + k^(2))/(gl))` |
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