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The distance between the two ends of the wings of a metallic aeroplane is 5 m. It is moving horizontally with a velocity of 360 km//hr. The carth's magnetic field all around its mouon is 4xx10^(-4) tesla and the angle of dip is 30^(@) Them, |
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Answer» vertical component of cerths magnetic field is `2 xx 10^(-4)T` `= (360xx1000)/(3600)=100m//s` DISTANCE between the two ends of the wings of the aeroplane. l = 5 m. Intensity of Tarth.s magnetic field, `I = 4 xx 10^(-4)` tesla. Angle of dip at that place, `theta = 30^(@)` Since the aeroplane is moving horizontally, it will cut the magnetic lines of force due to the vertical component of earth.s magnetic field only. Now, the vertical component of Earth.s magnetic field is given by ` V =I sintheta =4XX 10^(-4) xx sin30^(@) =2 xx 10^(-4)` tesla 
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