The distance between two consecutive atoms of the crystal lattice is 1.227Å. The maximum order of diffraction of electrons accelerated through 10^(4) volt is :

The distance between two consecutive atoms of the crystal lattice is 1

1.	The distance between two consecutive atoms of the crystal lattice is 1.227Å. The maximum order of diffraction of electrons accelerated through 10^(4) volt is :
Answer» 1 100 10 20 Solution :`d SIN theta =n lambda` `n_("MAX")=(d)/(lambda)=(d)/((12*27)/(SQRT(V)))=10`

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The distance between two consecutive atoms of the crystal lattice is 1.227Å. The maximum order of diffraction of electrons accelerated through 10^(4) volt is :

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