1.

The distance between two points differeing in phase by 60^(@) on a wave having 360

Answer»

0.72 m
0.18 m
0.12 m
0.36 m

Solution :V = 360 `ms^(-1)`, v = 500 Hz.
`thereforelambda = (u)/(v) = (360)/(500) = (18)/(25) ` m
`x = (lambda)/(2pi).phi (18)/(25). (PI //3)/(2pi ) = 0.12 `m
Hence CORRECT choice is (c).


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