The distance covered by an accelerating rocket is given by s= ut+1/2 a – InterviewSolution

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1.	The distance covered by an accelerating rocket is given by s= ut+1/2 at square. Find s when u=3 m/s , t=100 s and a =0.1 m/s square.
Answer» 3.8±1.1mExplanation:s=UT−21gt2u=1.11±0.01→%(Δu)=1.110.01×100=0.9009t=1.01±0.1→%(Δt)=1.0110=9.9009g=9.8±0.1→01→%(Δg)=9.80.1×100=1.0204s=(1.11±0.01)(1.01±0.1)−21(9.8±0.1)(1.01±0.1)2%(Δut)=10.8018%(Δgt2)=%(Δg)+2%(Δt)=20.8222(ut)m=1.11×1.01=1.1211→(ut)=1.1211±0.121021(GT2)m=4.9985→

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