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InterviewSolution
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The distance of planet Jupiter from the Sun is `5.2` times that of the earth. Find the period of revolution of Jupiter around the Sun. |
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Answer» Correct Answer - `11.86 years` Here, `R_(1)=R=`distance of earth from sun `R_(2)=5.2R T_(1)=1` year, `T_(2)=?` As `(T_(2)/T_(1))^(2)=(R_(2)/R^(1))^(3)=((5.2R)/(R))^(3)` `T_(2)=(5.2)^(3//2)xx1 year =5.2sqrt5.2 years` `T_(2)=11.86 years` |
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