InterviewSolution
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InterviewSolution
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The distance of the plane through (1,1,1) and perpendicular to the line `(x-1)/3=(y-1)/0=(z-1)/4` from the origin isA. `3/4`B. `4/3`C. `7/5`D. `1` |
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Answer» Correct Answer - C The given line is normal to the plane. So direction ratios of the normal to the plane are proportional to 3,0,4. The plane pases through (1,1,1). So its equation is `3(x-1)+0(y-1)+4(z-1)=0` or `3x+4z-7=0` Its distance `d` from the oriign is given by `d=(|-7|)/(sqrt(3^(2)+0^(2)+4^(2)))=7/5` |
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