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The distance of the point (1, 3) from the line 2x +3y = 6, measured parallel to the line 4x + y = 4, is A. 5/√13 units B. 3/√17 units C. √17 units D. √17/2 units |
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Answer» Correct option A. 5/√13 units Explanation: Required equation of line is: y – 3 = -4 (x – 1) ⇒ 4x + y = 7 Distance is measured from line 2x + 3y=6 Solving these equations, x = 3/2 & y = 1 Distance from the point (1, 3) = √(1/4 + 4) = √17/2 |
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