1.

The distance time graph of a particle at time t makes an angle of 45^(@) with time axis. After 1 second it makes an angle of 60^(@) with time axis, what is the acceleration of the particle ?

Answer»

`sqrt(3-1)`
`sqrt(3+1)`
`sqrt(3)`
1

Solution :Velocity is given by the slope of s-t graph initial velcotiy =U tan`45^(@)=1`,
Velocity after ONE sec=v=`TAN60^(@)=sqrt(3)`
`:. a=(v-u)/(t)=(sqrt(3-1))/(1)=(sqrt(3-1))`.


Discussion

No Comment Found

Related InterviewSolutions