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The distance travelled by a particle performing S.H.M. from its mean position in 2 second is equal to sqrt3/2A. Then what is its period ? |
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Answer» SOLUTION :`x=Asin omegat` `sqrt(3A)/2=A SIN omegatsqrt3/2=sin((2PI)/T)` `thereforesin(pi/3)=sin((2pi)/2T)` `pi/3=(2pi)/Txxt=(2pi)/Txx2` `T=4xx3=12sec.` |
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