1.

The distance travelled by a particle performing S.H.M. from its mean position in 2 second is equal to sqrt3/2A. Then what is its period ?

Answer»

SOLUTION :`x=Asin omegat`
`sqrt(3A)/2=A SIN omegatsqrt3/2=sin((2PI)/T)`
`thereforesin(pi/3)=sin((2pi)/2T)`
`pi/3=(2pi)/Txxt=(2pi)/Txx2`
`T=4xx3=12sec.`


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