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The distance travelled by a particle starting from rest and moving with an acceleration `(4)/(3) ms^-2`, in the third second is.A. `(10)/(3)m`B. `(19)/(3)m`C. 6mD. 4m |
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Answer» Correct Answer - A Distance covered in `n^(th)` second. `S_(n)=u+(1)/(2)a(2n-1),` `=0+(1)/(2)xx(4)/(3)(2xx3-1)` `=(1)/(2)xx(4)/(3)xx5=(10)/(3)m` |
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