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The domain of definition of f(x) = \(\sqrt{\frac{(x+1)(x-3)}{x-2}}\)is A. [-1, 2) ∪ [3, ∞) B. (-1, 2) ∪ [3, ∞) C. [-1, 2] ∪ [3, ∞) D. None of these |
Answer» Option : (A) Given, f(x) = √((x+1)(x-3)/(x-2)) Here, \({\frac{(x+1)(x-3)}{x-2}}\) ≥ 0 But, x ≠ 2 So, x ∈ [-1,2) ∪ [3,∞) |
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