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The domain of the function `f(x)=sqrt("In"_((|x|-1))(x^(2)+4x+4))` isA. `[-3,-1] cup [1,2]`B. `(-2, -1) cup [2,oo)`C. `(-oo,-3] cup (-2,-1) cup (2,oo)`D. None of these |
Answer» Correct Answer - C Case I: ` 0 lt |x|-1 lt 1 " or " 1 lt |x| lt 2` Then `x^(2)+4x+4 le 1` or `x^(2)+4x+3 le 0` or `-3 le x le -1` So, `x in (-2,-1) " (1)" ` Case II: ` |x|-1 gt 1 " or " |x| gt 2` Then `x^(2)+4x+4 ge 1` or `x^(2)+4x+3 ge 0` or `x ge -1 " or " x le -3` So, ` x in (-oo, -3] cup (2,oo)` So, ` x in (-oo, -3] cup (2,oo) " (2) " ` From (1) and (2), ` x in (-oo, -3] cup (-2, -1) cup (2,oo)`. |
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