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InterviewSolution
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The e.m.f and the standard e.m.f of a cell in the following reaction is 5 V and 5.06 V at room temperature, Ni(s) + 2Ag^+(n) → Ni^2+(0.02M) + 2Ag(s). What is the concentration of Ag^+ ions?(a) 0.0125 M(b) 0.0314 M(c) 0.0625 M(d) 0.0174 MI had been asked this question by my college director while I was bunking the class.My question is taken from Electrochemistry topic in section Electrochemistry of Chemistry – Class 12 |
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Answer» CORRECT option is (d) 0.0174 M The best I can EXPLAIN: GIVEN, Temperature T = 298K Concentration of Ni^2+ = (0.02M) E(cell) = E°(cell) – \(\frac{0.059}{n}\)LOG10 (Anode / Cathode) 5 = 5.06 – \(\frac{0.059}{2}\)log10(0.02 / [Ag^+]^2) [Ag^+]^2 = 0.0174 M. |
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