The e.m.f. of the cell, Zn / Zn2+(0.01M) //Fe2+(0.001M) Fe at 298 K is – InterviewSolution

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1.	The e.m.f. of the cell, Zn / Zn2+(0.01M) //Fe2+(0.001M) Fe at 298 K is 0.2957 thenthe value of equilibrium constant for the cellreaction is0, 2) 1000.2950.320,260.261) e00295 2) 1000295 3) 10002 4) 10093) 100.02954) 100.0591
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