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The earth (mass=6xx10^24 kg), revolves around the sun with angular velocity of 2xx10^(-7) rad/s in a circular orbit of radius 1.5xx10^8 km. What is the force exerted by the sun on the earth ? |
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Answer» Solution :The GRAVITATIONAL force exerted by the sun of the earth is EQUAL to the CP force `(mv^2)/r =mrw^2` `therefore F=mrw^2` `6xx10^24xx1.5xx10^8xx10^3xx(2xx10^(-7))^2` `3.6xx10^32` N. |
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