1.

The earth (mass =6xx10^(4)kg) revolves around the sun with an angular velocity of 2xx10^(-2) rad/s in a circular orbit of radius 1.5xx10^(8) km. The force excerted by the sun on the earth in newton, is

Answer»

`36xx10^(21)`
`27xx10^(39)`
zero
`18xx10^(25)`

SOLUTION :Mass (m)`=6xx10^(24)`kg,
Angular velocity`(omega)=2XX10^(-7)" rad"//s` and radius(R )`=1.5xx10^(8)" km"=1.5xx10^(11)" m"`.
FORCE exerted on the EARTH`=mRomega^(2)`
`=(6xx10^(24))xx(1.5xx10^(11))xx(2xx10^(-7))^(2)=36xx10^(21)N`


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