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The eccentricity of the earth's orbit is 0.0167. The ratio of its maximum speed in its orbit to its minimum speed is |
Answer» Solution : According to the law of conservation of ANGULAR MOMENTUM `mv_(1)r_(1)=mv_(2)r_(2)` `(v_(1))/(v_(2))=(r_(2))/(r_(1))=(a(1+e))/(a(1-e))` where e is eccentricity of the earth.s ORBIT `=((1+0.0167))/((1-0.0167))=1.034` |
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