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    				| 1. | The eccentricity of the locus of point `(2h+2,k),`where `(h , k)`lies on the circle `x^2+y^2=1`, is`1/3`(b) `(sqrt(2))/3`(c) `(2sqrt(2))/3`(d) `1/(sqrt(3))`A. `1//3`B. `sqrt(2)//3`C. `2sqrt(2)//3`D. `1//sqrt(3)` | 
| Answer» (1) Let p =3h+2 and q=k or `h=(p-2)/(3) and k=q` Since (h,k) lies on `x^(2)+y^(2)=1` `h^(2)+k^(2)=1` or `((p-2)/(3))^(2)+q^(2)=1` The locus is (2) `((x-2)/(3))^(2)+y^(2)=1` which has eccentricity `e=sqrt(1-(1)/(9))=(2sqrt(2))/(3)` | |