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The effect of temperature on equilibrium constant is expressed as`(T_(2)gtT_(1))` log`K_(2)//K_(1)=(-DeltaH)/(2.303)[(1)/(T_(2))-(1)/(T_(1))]`. For endothermic, false statement isA. `[(1)/(T_(2))-(1)/(T_(1))]="positive"`B. `DeltaH="positive"`C. log`K_(2)gt"log"K_(1)`D. `K_(2)gtK_(1)` |
Answer» Correct Answer - A `"log K_(2)//"logK_(1)=(-DeltaH)/(2.303)[(1)/(T_(2))-(1)/(T_(1))] rArr DeltaH="positive"` |
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