1.

The efficiency of a Carnot engine is 50% and temperature of sink is 500 K. If temperature of source is kept constant and its efficiency raised to 60%, then the required temp. of sink will be:

Answer»

100 K
600 K
400 K
500 K

Solution :`eta=1-(T_(2))/(T_(1)) RARR (50)/(100)=1-(500)/(T_(1)) rArr T_(1)=1000 K`
`eta_(2)=1-(T_(2).)/(T_(1)) rArr (60)/(100) =1-(T_(2).)/(1000) rArr T_(2).=400 K`
`therefore` Correct CHOICE is (C ).


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