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The efficiency of a Carnot engine operating between temperatures of `100^(@)C` and `-23^(@)C` will beA. `(100-23)/(100)`B. `(100-23)/(373)`C. `(100+23)/(373)`D. `(100+23)/(100)` |
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Answer» Correct Answer - C `eta=(T_(1)-T_(2))/(T_(1))=((273+100)-(273-23))/(273+100)=(100+23)/(373)` |
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