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The efficiency of an ideal heat engine working between the freezing point and boiling point of water, isA. `6.25%`B. `20%`C. `26.8%`D. `12.5%` |
Answer» Correct Answer - C Efficiency of ideal heat engine, `eta=(1-(T_(2))/(T_(1)))` `T_(2)` : Sink temperature `T_(1)`: Source temperature `% eta=(1-(T_(2))/(T_(1)))xx100` `=(1-(273)/(373))xx100` `=((100)/(373))xx100=26.8%` |
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