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    				| 1. | The efficiency of an ideal heat engine working between the freezing point and boiling point of water, isA. `6.25%`B. `12.5%`C. `20 %`D. `26.8%` | 
| Answer» Correct Answer - D `eta = 1 - (T_(2))/(T_(1)) = 1 - (273)/(373) = (100)/(373) = (100 xx 100)/(373) = 26.8%` | |