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The elctrical resistance of a column of `0.05 M N aOH ` solution of diameter `1 cm` and length `50 cm` is `5.55 xx 10^(3)ohm`. Calculate its resisteivity , conductivity, and molar conductivity. |
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Answer» Area of cross-section `=pir^(2)=3.14xx(0.5)^(2)cm^(2)=0.785cm^(2)` We know, `R=rhoxx(1)/(A),5.55xx10^(3)=rhoxx(50)/(0.785)` `"Resistivity",rho=87.135"ohm cm"` `"Conductivity k"=(1)/(rho)=(1)/(87.135)-0.01148"S cm"^(-1)` Molar conductivity `Lambda_(m)` can be calculated as, `Lambda_(m)=kxx(1000)/(M)=0.01148xx(1000)/(0.05)` `=229.6"S cm"^(2)"mol"^(-1)` |
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