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The elctrical resistance of a column of `0.05 M N aOH ` solution of diameter `1 cm` and length `50 cm` is `5.55 xx 10^(3)ohm`. Calculate its resisteivity , conductivity, and molar conductivity.

Answer» Area of cross-section `=pir^(2)=3.14xx(0.5)^(2)cm^(2)=0.785cm^(2)`
We know, `R=rhoxx(1)/(A),5.55xx10^(3)=rhoxx(50)/(0.785)`
`"Resistivity",rho=87.135"ohm cm"`
`"Conductivity k"=(1)/(rho)=(1)/(87.135)-0.01148"S cm"^(-1)`
Molar conductivity `Lambda_(m)` can be calculated as,
`Lambda_(m)=kxx(1000)/(M)=0.01148xx(1000)/(0.05)`
`=229.6"S cm"^(2)"mol"^(-1)`


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