1.

The electric dipole moment of an electron and proton 4.3 nm apart is

Answer»

`6.88xx10 ^(-28) Cm`
` 2.56 XX 10^(-29)C^(2) m^(-1) `
` 3.72 xx 10 ^(-14)C m^(-1) `
` 1.1 xx 10 ^(-46)C^(2) m `

Solution :Here `|q_1|=|q_2| =1.6 xx 10 ^(-19)C ` and distance between two charges is `2a =4.3 nm =4.3 xx 10^(-9)m`
` therefore ` Dipole MOMENT ` p=1.6 xx10 ^(-19) xx 4.3 xx10 ^(-9)C m =6.88 xx10 ^(-28) C m. `


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