1.

The electric dipole moment of an HCl atom is 3.4 xx 10^(-30) Cm. The charges on both atoms are unlike and of same magnitude. Magnitude of this charge is ........The distance between the charges is 1 A.

Answer»

<P>`1.7 xx 10^(-20)` C
`3.4 xx 10^(-20)` C
`6.8 xx 10^(-20)` C
`3.4 xx 10^(-10)` C

Solution :`p = 3.4 xx 10^(-30)` cm
`2a = 1.0A = 10^(-10)` m
q=?
p=(2a)q
`THEREFORE q = p/(2a) = (3.4 xx 10^(-30))/10^(-10) = 3.4 xx 10^(-20)` C


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