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The electric field and electric potential at any point due to a point charge kept in air si 20 N C^(-1) and 10 J C^(-1) respectively. Compute the magnitude of this charge. |
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Answer» SOLUTION :Here electric field `E = Q/(4pi epsi_0 r^2) = 20 N//C` …(i) and electric potential`V = Q/(4pi epsi_0r) = 10 J//C`…(ii) Dividing (ii) by (i), we get `r = 10/20 = 0.5 m` Substituding value of r in (ii), we get `Q = 4pi epsi_0. r XX 10 = (0.5 xx 10)/(9 xx 10^9) = 5.55 xx10^(-10) C.` |
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