Saved Bookmarks
| 1. |
The electric field in a certain region is acting radially outward and is given by E = Ar. A charge contained in a shepere of radius 'a' centred at the origin of the field, will be given by : |
|
Answer» `Aepsilon_(0)a^(2)` since electric FIELD is RADIAL. It is always perpendicular to the surface. So, `phi =Ar.(4pir^(2))` `phi = A(a)(4pir^(2))` `phi =A4pia^(3)` (as r=a) Now according to gauss law `phi = (q_(in))/epsilon_(0) RARR q_(in) =phi.epsilon_(0)` So,= `q_(in) =Apia^(3)epsilon_(0)` |
|