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The electric field in a region is given by vec(E )= E_(0) (x)/(L) hat(i). Find the charge contained inside a cubical volume bounded by the surface x=0, x= L, y= 0, y= L, z= 0 and z=L. |
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Answer» SOLUTION :At x=0, E=0 and at x= l, `vec(E )= E_(0) hat(i)` The direction of the FIELD is along the x-axis, so it will cross the yz-face of the cube. The FLUX of this field  `phi = phi_("left face") + phi_("right face") = 0 + E_(0)L^(2) = E_(0)L^(2)` By Gauss.s law `phi= (q)/(in_(0)) THEREFORE q= in_(0) phi = in_(0) E_(0)L^(2)` |
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