InterviewSolution
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InterviewSolution
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The electric field in a region is given by vec(E ) = E_0 x/L hati . Find the charge contained inside a cubical volume bounded by the surface x = 0, x = L, y = 0 , y = L, z = 0 and z = L. |
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Answer» Solution :At x = 0 , E = 0 and at `x = l , vec(E ) = E_0 HATI` The direction of the field is along the x-axis , so it will cross the YZ- face of the cube. The FLUX of this field. `phi = phi_("left face") + phi_("right face") = 0 + E_0 L^2 = E_0 L^2` By Gauss.s law, `phi = q/(in_0) :. q = in_0 phi = in_0 E_0L^2`. 
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