1.

The electric field intensity at a point 20 cm away from a charge of 2 xx 10^(-5) C is

Answer»

`4.5 XX 10^(6) NC^(-1)`
`3.5 xx 10^(5) NC^(-1)`
`3.5 xx 10^(6) NC^(-1)`
`4.5 xx 10^(5) NC^(-1)`

Solution :`E = (q)/(4 pi epsilon_(0) r^(2)) = (9xx 10^(4) xx 2 xx 10^(-5))/((0.2)^(2)) = 4.5 xx 10^(6) NC^(-1)`


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