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The electric field intensity produced by the radiations coming from 100 W bulb at a 3 m distance is E. The electric field intensity produced by the radiations coming from 50 W bulb at the same distance is:(a) (E )/(2) (b) 2E (c) (E )/(sqrt(2)) (d) sqrt(2)E |
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Answer» <P>`(E )/(2)` `THEREFORE P PROP E^(2)` `therefore (P_(2))/(P_(1))=((E_(2))/(E_(1)))^(2)` `(50)/(100)=((E_(2))/(E ))^(2)` `((1)/(2))^(1//2)=(E_(2))/(E )` `therefore E_(2)=(E )/(sqrt(2))` |
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