1.

The electric field intensity produced by the radiations coming from 100 W bulb at a 3 m distance is E. The electric field intensity produced by the radiations coming from 50 W bulb at the same distance is:(a) (E )/(2) (b) 2E (c) (E )/(sqrt(2)) (d) sqrt(2)E

Answer»

<P>`(E )/(2)`
2E
`(E )/(sqrt(2))`
`sqrt(2)E`

Solution :Electric power `P=(E^(2))/(R )`
`THEREFORE P PROP E^(2)`
`therefore (P_(2))/(P_(1))=((E_(2))/(E_(1)))^(2)`
`(50)/(100)=((E_(2))/(E ))^(2)`
`((1)/(2))^(1//2)=(E_(2))/(E )`
`therefore E_(2)=(E )/(sqrt(2))`


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