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The electric field part of an electromagnetic wave in a medium is represented by E_(x) = 0,E _(y)= 2.5 (N)/( C) cos [(2 pi xx 10^(6) rad/s ]t - ( pi xx 10^(-2) (rad)/m) x]E_(z) = 0 The wave is

Answer»

moving along the + xdireaction with FREQUENCY ` 10^(6)` Hz and wavelength 100 m .
moving along + XDIRECTION with frequency ` 10^(6) ` Hzand wavelength 200 m .
movingalong-xdirection with frequency ` 10^(6)` Hz and wavelength 200 m .
moving along + ydirection with frequency`2 pi xx 10^(6)`Hzand wavelength 200 m .

Solution :Given . ` E_(x) = 0`
` E_(y) = 2.5 N/C cos [(2PI xx 10^(6) (rad)/s) t - ( pi xx 10^(-2) (rad)/m)x]`
This SHOWS that the wave is propagating along + direction. Comparing the givenequation with ` E_(y) = E_(0)cos(omegat - kx),`we get
` omega =2 pi xx 10^(6) or v = 10^(6) Hz `
` and k = pi xx 10^(6) or 2 pi v= 10^(-2) m `
`or lamda= ( 2pi)/( pi xx 10^(-2)) = 200 m`


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