InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The electric field part of an electromagnetic wave in a medium is represented by `E_(x)=0,` `E_(y)=2.5(N)/(C) cos[(2pixx10^(6)(rad)/(m))t-(pixx10^(-2)(rad)/(s))x]` `E_(z)=0`. The wave isA. Moving along –x direction with frequency `10^(6)` Hz and wavelength 200mB. Moving along y direction with frequency `2pi xx10^(6)` Hz and wavelength 200mC. Moving along x direction with frequency `10^(6)` Hz and wavelength 100mD. Moving along x direction with frequency `10^(6)` Hz and wavelength 200m |
|
Answer» Correct Answer - D As the coefficient of x is negative , it is moving along +ve x-axis and equating the equation `E_(y)=2.5 cos [(2 pi xx 10^(6))t-(pixx10^(-2))x]` with `y=A cos (omegat-kx)` `omega=2 pi xx 106` `implies f=(omega)/(2pi)=10^(6)Hz ` `k= pi xx 10^(-2)` ` lambda=(2pi)/(k)` `=(2pi)/(pi xx 10^(-2))=200m` |
|