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The electric force experienced by a charge of 1.0xx10^(-6) C is 1.5 xx 10^(-3) N . Find the magnitude of the electric field at the position of the chaerge. |
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Answer» SOLUTION :`F_e=thetaE, E=(F_e)/THETA=(1.5xx10^-3)/(1.0xx10^-6 )` ` =1.5xx10^3N//C` |
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