1.

The electrical conductivity of a semiconductor increases when e.m . Radiation of wavelength shorter than 2480 nm is incident on it . The band gap in (eV) for semiconductor is :

Answer»

0.5
0.7
1.1
2.5

Solution :Band gap = energy of photon
`=(hc)/LAMDA=(6.62xx10^(-34)xx10^8)/(2480xx10^(-9)xx1.6xx10^(-9))~~0.5eV`


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