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The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480 nm is incident on it. The band gap (in eV) for semi-conductor is |
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Answer» 0.9 Here, `lamda = 2480 nm = 2480 xx10^(-9) m = 248 xx10^(-8)m` `:.E_g=(6.6xx10^(-34)xx3xx10^(8))/(248xx10^(-8))=7.984xx10^(-20)J` `=(7.984xx10^(-20))/(1.6xx10^(-19))eV=0.499eV = 0.5 eV` |
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