Saved Bookmarks
| 1. |
The electrostatic force on a small sphere of charge 0.4muC due to another small sphere of charge0.8muCin air is 0.2 N. a. What is the distance between the two spheres? b. What is the force on the second sphere due to the first? |
|
Answer» Solution :`q_(1)=0.4 muC=0.4 xx 10^(-6)C, q_(2)=-0.8 MU C=-0.8 xx 10^(-6)C, F=0.2N` a. `F=9 xx 10^(6) (q_(1)q_(2))/(r^(2))` `r^(2)=9 xx 10^(9) xx (q_(1)q_(2))/(F)=(9 xx 10^(9) xx 0.4 xx 10^(-6) xx 0.8 xx 10^(-6))/(0.2) =14.4 xx 10^(-3) =144xx 10^(-4) m^(2) r=12 xx 10^(-2)m` b. 0.2N, attractive. |
|